Question

What is the mass of a solid ball of iron with a radius equal to 18 cm if it is known that the density of iron is 7800 kg/m

Answer 1

60.6528 kg

Explanation:

Assuming the solid ball of iron is a sphere with a radius of 18 cm (or 0.18 m), we can compute the volume of the sphere:

`V=(4)/(3)\pi r^3\\\\V=(4)/(3)\pi ((18)/(100))^3\\\\V=(4)/(3)\pi (0.005832)\\\\V=0.007776`

Therefore, the volume of the solid ball is 0.007776 m³

Since we know that density is mass/volume, then we can find the mass of the iron:

`\rho=(mass)/(volume)\\ \\7800\: kg/m^3=(mass)/(0.007776\: m^3)\\\\mass=60.6528\:kg`

Thus, the mass of the solid ball of iron is 60.6528 kg