Question

Write the quadratic in standard form (x-8)^2 and please explain how you got it if u can cuz im trying to learn .

Answer 1

`x^(2) -16x +64 = 0`

Explanation:

`(x-8)^(2)` is the same as saying
`(x-8)(x-8)`

therefore, you use FOIL(first outside inside last) to get

`x^(2) -8x-8x+64`

which is
`x^(2) -16x +64 = 0` in standard form