Question

Hershberger's Farms plans to mix two types of food to make a mix of low cost feed for the animals in his farm. A bag of food costs $10 and contains 40 units of protein, 20 units of minerals and 10 units of vitamins. A bag of food B costs $12 and contains 30 units of proteins, 20 units of minerals and 30 units of vitamins. Daily minimum requirements consist of 150 units of proteins, 90 units of minerals and 60 units of vitamins.

a. Based on the lowest possible cost, how many bags of food A and food B should be consumed by the animals each day?
b. What is the overall cost? $46.50
c. Was there any unused resources?

Answer 1

Following are the responses to the given choices:

Step-by-step explanation:

For point a:

It is possible to say that as the material unit in either bag are same, the minimum bag number is 90 /20 = 4.5

rounded off=Minimum 5 bags

They will try to use all of these bags as the cost of bag A is poor.

When we have five bags of protein A, therefore the vitamin requirements were n’t fulfilled.

Currently, using 4 bags of A and 1 B bag, protein, vitamin and mineral obligations are fulfilled. They all are met.

Therefore, 4 food bags A and 1 food bag B need to be consumed due to the lowest cost.

For point b:

Cost total:

`=( 4 * 10 ) + ( 1 * 12)\\\\=40 +12\\\\= \$52`

For point c:

The following are unused resources:

`\text{Protein = Bag A + Bag B - Consumption}\\\\= 160 + 30 - 150\\\\=190-150\\\\= 40\\\\Minerals = 10 \\\\vitamins = 10`