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4 votes
Match each equation to its description

A.Circle centered at (0,-4) with radius of 3
1.(x-1)^2 + y^2=9
2.x^2+(y+4)^2=9
3. (x-1) +( y - 4)^2=3
4.(x - 1)^2+(y - 4)^2=9
5.(x - 1)^2 + (y + 4)^2=3
Which is the correct answer
A.1
B.2
C.3
D.4
E.5

1 Answer

5 votes

Answer:


\boxed {\boxed {\sf B. \ 2: x^2+(y+4)^2=9}}}

Explanation:

The equation for a circle is:


(x-h)^2+(y-k)^2=r^2

Where (h, k) is the center and r is the radius.

We know that the center of the circle is (0, -4) and the radius is 3. Therefore:

  • h= 0
  • y= -4
  • r=3

Substitute the values into the formula.


(x-0)^2+(y--4)^2=(3)^2

Solve the first parentheses.

  • (x-0)² = (x)²= x²


x^2+(y--4)^2=(3)^2

Solve the next parentheses.

  • (y--4)² = (y+4)²


x^2+(y+4)^2=(3)^2

Solve the exponent.

  • (3)²= 3*3=9


x^2+(y+4)^2=9

This is the finished equation, which corresponds with number 2. Choice B (2): x²+(y+4)²= 9 is correct.

User Manz
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