Question

the mass concentration the mass concentration for a solution containing 45 g of calcium carbonate is 100 cm3 ​

Answer 1

Answer: The mass concentration for a solution containing 45 g of calcium carbonate for 100
`cm^(3)` is 0.045 M.

Step-by-step explanation:

Given: Mass of calcium carbonate = 45 g

Volume =
`100 cm^(3)`

Convert
`cm^(3)` into L as follows.

`1 cm^(3) = 0.001 L\\100 cm^(3) = 100 cm^(3) * (0.001 L)/(1 cm^(3))\\= 0.1 L`

Moles of calcium carbonate (molar mass = 100 g/mol) is as follows.

`No. of moles = (45 g)/(100 g/mol)\\= 0.45 mol`

Molarity is the number of moles of solute present in a liter of solution.

Hence, molarity (or mass concentration) of given solution is calculated as follows.

`Molarity = (no. of moles)/(Volume (in L))\\= (0.45 mol)/(0.1 L)\\= 0.045 M`

Thus, we can conclude that the mass concentration for a solution containing 45 g of calcium carbonate for 100
`cm^(3)` is 0.045 M.