Answer:
334.7g of Calcium Hydroxide are needed
Step-by-step explanation:
Based on the reaction:
2Ca(OH)2 + 2Cl2 → Ca(ClO)2 + CaCl2 + 2H2O
2 moles of chlorine react with 2 moles of calcium hydroxide.
To solve this question we must find the moles of chlorine in 300.0g. These moles = Moles of Ca(OH)2. With the moles of calcium hydroxide we can find its mass as follows:
Moles Cl₂ (Molar mass: 70.90g/mol)
300.0g Cl₂ * (1mol / 70.90g) = 4.2313 moles Cl₂ = Moles Ca(OH)₂
Mass Ca(OH)₂ (Molar mass: 74.093g/mol)
4.2313 moles Ca(OH)₂ * (74.093g / mol) =
334.7g of Calcium Hydroxide are needed