118k views
16 votes
sale on watches 10% off marked price + 20% off the discounted price what will a watch marked at $1,200.00cost?

User Dzuritaa
by
7.9k points

2 Answers

6 votes

Answer:

$864

Explanation:

100-10 = 90/100= 0.9 (multiplier)

1200*0.9= 1080

100-20 = 80/100= 0.8 (2nd multiplier)

1080*0.8= 864

hope this helps

User Sira Lam
by
8.2k points
5 votes

Answer:


</p><p>[tex] \large{\boxed{\sf Hypotenuse = 16.97\ cm }}

Hypotenuse=16.97 cm

Explanation:

Here it is given that the area of a right isosceles ∆ is 72 cm² . Let us assume that each equal side is x . Therefore the height and the base of the ∆ will be same that is x .

p


\begin{gathered}\sf\qquad\longrightarrow

Area =\dfrac{1}{2}(base)(height)\\\end{gathered}⟶Area=21(base)(height)


\begin{gathered}\sf\qquad\longrightarrow


72cm^2=(1)/(2)(x)(x)\\\end{gathered}

⟶72cm2=21(x)(x)


\begin{gathered}\sf\qquad\longrightarrow x^2=

144cm^2\\\end{gathered}⟶x2=144cm2


\begin{gathered}\sf\qquad\longrightarrow x


=√(144cm^2)\\\end{gathered}⟶x=144cm2


\sf\qquad\longrightarrow \pink{x = 12cm }⟶x=12cm

Hence we may find hypotenuse using Pythagoras Theorem as ,


\sf\qquad\longrightarrow h =√( p^2+b^2)⟶h=p2+b2

Here p = b = 12cm ,


\begin{gathered}\sf\qquad\longrightarrow h =√( (12cm)^2+(12cm)^2)\\\end{gathered}

⟶h=(12cm)2+(12cm)2


\begin{gathered}\sf\qquad\longrightarrow h


=√(144cm^2+144cm^2)\\\end{gathered}

⟶h=144cm2+144cm2


\begin{gathered}\sf\qquad\longrightarrow h

=\sqrt{288cm^2}\\\end{gathered}⟶h=288cm2


\sf\qquad\longrightarrow \pink{ hypotenuse=

16.97cm }⟶hypotenuse=16.97cm

Hence the hypotenuse is 16.97 cm .

[/tex]

User Krokodil
by
7.7k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories