Answer:
![</p><p>[tex] \large{\boxed{\sf Hypotenuse = 16.97\ cm }}](https://img.qammunity.org/2023/formulas/mathematics/high-school/y1x9e09l6e3l87sfps0enzd7q0org4e436.png)
Hypotenuse=16.97 cm
Explanation:
Here it is given that the area of a right isosceles ∆ is 72 cm² . Let us assume that each equal side is x . Therefore the height and the base of the ∆ will be same that is x .
p
![\begin{gathered}\sf\qquad\longrightarrow]()
Area =\dfrac{1}{2}(base)(height)\\\end{gathered}⟶Area=21(base)(height)
![\begin{gathered}\sf\qquad\longrightarrow]()

⟶72cm2=21(x)(x)
144cm^2\\\end{gathered}⟶x2=144cm2
![\begin{gathered}\sf\qquad\longrightarrow x]()


Hence we may find hypotenuse using Pythagoras Theorem as ,

Here p = b = 12cm ,

⟶h=(12cm)2+(12cm)2
![\begin{gathered}\sf\qquad\longrightarrow h]()

⟶h=144cm2+144cm2
![\begin{gathered}\sf\qquad\longrightarrow h]()
=\sqrt{288cm^2}\\\end{gathered}⟶h=288cm2

16.97cm }⟶hypotenuse=16.97cm
Hence the hypotenuse is 16.97 cm .
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