Question

Simply the following​

Answer 1

n

Explanation:

`\Bigg[\bigg[ [1/n]^(-1)\bigg]^(-1) \Bigg] ^(-1)`

=
`\bigg[ [1/n]^(-1)\bigg]^((-1) (-1))`

=
`\bigg[ [1/n]^(-1)\bigg]^(1)`

=
`[1/n]^(-1* 1)`

=
`[1/n]^(-1)`

=
`[1/n^(-1)]`

= n

Hope it helps you in your learning process