Answer:
0.0208
Explanation:
Using the formula for calculating margin of error is expressed as;
M = z * √p(1-p)/n
z is the z score at 90 % interval
p is the proportion
n is the sample size
p = 0.2
n = 1000
z = 1.645
M = 1.645 * √0.2(1-0.2)/1000
M = 1.645 * √0.2(0.8)/1000
M = 1.645 * 0.01264
M = 0.0208
Hence the margin of error is 0.0208