A person on a bike (m=90kg) is traveling 4m/s at the top of a 2m hill. What is his/her kinetic energy?

asked May 21, 2022 154k views

2 votes

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6 votes

Ke =(1/2 )mv^2
1/2(90*4)^2
720
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Arathi answered May 21, 2022

4.3k points

3 votes

Answer:

Ek = 720J

Step-by-step explanation:

Ek = 0.5mv^2

Ek = 0.5(90)(4)^2

Ek = 720J

AudioDroid answered May 26, 2022

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