A person on a bike (m=90kg) is traveling 4m/s at the top of a 2m hill. What is his/her kinetic energy?

asked May 21, 2022 154k views

2 votes

5.5k points

Please log in or register to add a comment.

6 votes

Ke =(1/2 )mv^2
1/2(90*4)^2
720
Have a nice day

Arathi answered May 21, 2022

5.7k points

3 votes

Answer:

Ek = 720J

Step-by-step explanation:

Ek = 0.5mv^2

Ek = 0.5(90)(4)^2

Ek = 720J

AudioDroid answered May 26, 2022

5.5k points

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

6.5m questions

8.5m answers