Question

When a constant force acts upon an object, the acceleration of the object varies inversely with its mass. When a certain constant force acts upon an object with mass 7 kg, the acceleration of the object is
`8 m/s^(2)`. If the same force acts upon another object whose mass is 4 kg, what is this object's acceleration?

Answer 1

14m/
`s^(2)`

Explanation:

F = ma

Mass1: F1 = (7kg)*(8m/
`s^(2)`)

Mass2: F2 = (4kg)*a

The same force, so F1 = F2

(7kg)*(8m/
`s^(2)`) = (4kg)*a

a = (7kg)*(8m/
`s^(2)`)/(4kg)

a = (7/4)*(8m/
`s^(2)`)

a = 14m/
`s^(2)`