Question

At what voltage can a 10 μF capacitor be energized to 0.45 J?

Answer 1

Given :

Capacity of capacitor is,
`C = 10\ \mu F`.

To Find :

At what voltage can a 10 μF capacitor be energized to 0.45 J.

Solution :

We know, energy in capacitor is given by :

`E = (CV^2)/(2)`

So,

`V = \sqrt{(2E)/(C)}\\\\V = \sqrt{(2* 0.45)/(10)}\ \mu V\\\\V = 0.3 \ \mu V`

Therefore, voltage required is
`0.3 \ \mu V` .