Question

Please help me pleaseee

Answer 1

Given:

The quadratic function is:

`f(x)=(x+2)^2+1`

To find:

The graph of the given quadratic function.

Solution:

The vertex form of a quadratic function is:

`f(x)=a(x-h)^2+k` ...(i)

Where, a is a constant and (h,k) is the vertex of the graph of the quadratic function.

We have,

`f(x)=(x+2)^2+1` ...(ii)

On comparing (i) and (ii), we get

`a=1`

`h=-2`

`k=1`

Now,

`(h,k)=(-2,1)`

It means the vertex of the graph of the given function is at point (-2,1).

Only in graph C, the vertex of the parabola is at (-2,1).

Therefore, the correct option is C.