Question

A car is travelling at 27m/s and decelerates at a=5m/s2 for a distance of 10m. Calculate its final velocity. (Hint does deceleration imply that the acceleration is positive or negative?)

Answer 1

If deceleration = 5 m/s²

then acceleration = -5 m/s²

According to third law of motion,

= v² = 2as + u²

= v² = 2×-5×10 + 27²

= v² = -100 + 729

= v =√ 629

= 25.08 m/s