Answer:
4x-2y=8
or, 4x = 8+2y
or x = 8+2y/4-----(eq.1)
2x-3y=12-----(eq.2)
Now,
putting value of eq.1 in eq.2, we get
2x-3y=12
or, (8+2y/4)-3y = 12
or, 8-10y/4=12
or, 8-10y=12×4
or,8-10y=48
or,-10y=48-8
or,y=40/-10
or, y = -4
again,
2x-3y=12
or, 2x-3×-4=12
or, 2x+12=12
or, x=0
In 1st option
4x-2y=8
or,4×0-2×-4=8
or,0+8=8
8=8
2x-3y=12
2×0-3×-4=12
0+12=12
12=12
So 1st option is true