Question

A sample of gas occupies 200 L at 780 mm Hg and 280 K. What is the new volume, in liters, of the gas at 810 mm Hg and 300 K?

Answer 1

Given :

A sample of gas occupies 200 L at 780 mm Hg and 280 K.

To Find :

The new volume, in liters, of the gas at 810 mm Hg and 300 K.

Solution :

We know, by ideal gas equation :

`PV = nRT`

Since, every thing is constant except
`nR` .

So,

`(P_1V_1)/(T_1) = (P_2V_2)/(T_2)`

Putting all given values we get :

`V_2 = (T_2)/(T_1)* (P_1)/(P_2)* V_1\\\\V_2 = (300)/(280)* (780)/(810)* 200\ L\\\\V_2 = 206.35 \ L`

Therefore, the new volume is 206.35 L.