Question

Amy has a jar of jelly beans In the jar there are 14 red 22 blue 12 yellow and 8 green What is the probability that Amy will randomly select a red jelly bean eat it and then select a green jelly bean?

A. 8/43
B 5/43
C. 3/43
D. 9/55
F. 7/55
G. 2/55

Answer 1

The probability that Amy will select and eat a red jelly bean and then select a green jelly bean is 2/55.

Step-by-step explanation:

The question is asking for the probability that Amy will randomly select a red jelly bean, eat it, and then select a green jelly bean from a jar with a specified number of colored jelly beans. Initially, the total number of jelly beans in the jar is 56 (14 red, 22 blue, 12 yellow, 8 green). When selecting a red jelly bean first, the probability is 14/56. After eating the red jelly bean, there are now a total of 55 jelly beans left. The probability that the next jelly bean is green is then 8/55. To find the overall probability of both events happening in sequence, we multiply the probabilities of each individual event: (14/56) × (8/55) = 2/55, which is the correct answer.