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TanA+tanB+tanAtanB=1 If A+B=45 degree​

User Ribose
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Answer:

See below

Explanation:


\tan A+\tan B + \tan A.\tan B = 1\\\\ \implies \: \tan A + \tan B = 1 - \tan A.\tan B \\ \\ \implies \: (\tan A + \tan B)/( 1 - \tan A.\tan B ) = 1\\ \\ \implies \: \tan (A + B) = 1 \\ \\ \implies \: \tan (A + B) =\tan 45 \degree \\ \\ \implies \: A + B = 45 \degree \\ \\ thus \: proved

User Kcm
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