Question

What would the Kc value be from this reaction: H2 + I2 = 2HI.

(Because of the coefficient "2" in front of HI, you will have to square the concentration
of HI to find Kc. Kc = ?

Answer 1

Answer: The value of
`K_(c)` for the given reaction is
`K_(c) = ([HI]^(2))/([H_(2)][I_(2)])` .

Step-by-step explanation:

The ratio of concentration of products and reactants raised to the power of their concentration is called equilibrium constant.

It is denoted by the symbol
`'K_(c)'`.

For example,
`H_(2) + I_(2) \rightarrow 2HI`

The expression for
`K_(c)` of this reaction is as follows.

`K_(c) = ([HI]^(2))/([H_(2)][I_(2)])`

So, by putting the respective concentrations of the species involved in the reaction it is possible to determine the value of
`K_(c)` for the given reaction.

Thus, we can conclude that the value of
`K_(c)` for the given reaction is
`K_(c) = ([HI]^(2))/([H_(2)][I_(2)])` .