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7. In A.ABC. JB and KA are medians, JK = 10x - 12, AB = 9x + 18, JM = 21, KM = 23. AJ = 60. and

BK - 52

a. Find JK and AB. Round decimal answers to the nearest tenth.
b. Find the perimeter of AABC.
c. Find the perimeter of AABM.

7. In A.ABC. JB and KA are medians, JK = 10x - 12, AB = 9x + 18, JM = 21, KM = 23. AJ-example-1
User Euskalduna
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1 Answer

4 votes

Answer:

A) JK and AB =


[tex] \boxed{( \theta) = \f{12}{( \theta)} } So, =》
(10)/(5) = (1)/( \( \theta) ) =》
\( \theta) = (5)/(2)[/tex]

B) AABC


[tex] \boxed{( \theta) = {1}{( \theta)} } So,
23}{-18=\\Ans } \boxed

C) AABM:


[tex] e \fbox{: } The value of k for which
\sin(jm) = \cos(x) is
(\p)/(2) ans[/tex]

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User Hekmat
by
6.8k points