Question

PLEASE HELP ME RN!!!!!

Answer 1

32, 2√7

Step-by-step explanation:

given:
`\sf \bold x^2+6x+2=0`

using quadratic formula:
`\boxed{\boxed{\sf x = ( -b \pm √(b^2 - 4ac))/(2a)}}`

solve using the equation:

• 
  `\sf x_(1,\:2)=(-6\pm √(6^2-4\cdot \:1\cdot \:2))/(2\cdot \:1)`

• 
  `\sf x_1=(-6+2√(7))/(2\cdot \:1),\:x_2=(-6-2√(7))/(2\cdot \:1)`

• 
  `\sf x=-3+√(7),\:x=-3-√(7)`

given a > β

• so -3+√7 > -3-√7
• a = -3+√7 and β = -3-√7

solve:

• (-3+√7)² + ( -3-√7)²
• 32

and

• -3+√7 - -3-√7
• 2√7