Question

S(s)+3F2(g)->SF6(g) how many mol of F2 are required to react completely with 2.30 mol of S?

Answer 1

Answer: There are 6.9 mol of
`F_(2)` are required to react completely with 2.30 mol of S.

Step-by-step explanation:

The given reaction equation is as follows.

`S(s) + 3F_(2)(g) \rightarrow SF_(6)(g)`

Here, 1 mole of S is reaction with 3 moles of
`F_(2)` which means 1 mole of S requires 3 moles of
`F_(2)`.

Therefore, moles of
`F_(2)` required to react completely with 2.30 moles S are calculated as follows.

`1 mol S = 3 mol F_(2)\\2.30 mol S = 3 mol F_(2) * 2.30 \\= 6.9 mol F_(2)`

Thus, we can conclude that there are 6.9 mol of
`F_(2)` are required to react completely with 2.30 mol of S.