Question

14

Determine the distance between L(1, 4, 7) and M(2, 9, 8) on a three-dimensional plane.

XY = √(x2 – x, )²+ (y2 – yı)2 + (x2 – 21)2

Answer 1

Distance LM = 5.20 unit (Approx.)

Explanation:

Given coordinates;

L(1, 4, 7) and M(2, 9, 8)

Find:

Distance LM

Computation:

Distance between three-dimensional plane = √(x2 - x1)² + (y2 - y1)² + (z2 - z1)²

Distance LM = √(2 - 1)² + (9 - 4)² + (8 - 7)²

Distance LM = √(1)² + (5)² + (1)²

Distance LM = √1 + 25 + 1

Distance LM = √27

Distance LM = 3√3 unit

Distance LM = 3(1.732)

Distance LM = 5.196

Distance LM = 5.20 unit (Approx.)