Question

A wire 48 m long carries a current of 18 A from west to east.

Answer 1

Explanation:

Given that,

The length of a wire, L = 48 m

Current in the wire, I = 18 A (west to east)

The magnetic field in the wire, B =
`8.3* 10^4\ T` (towards south)

The magnetic force acting on the wire is given by :

`F=I(L* B)\\\\F=48\cdot18\cdot8.3\cdot10^(-4)\ N\\\\F=0.71\ N`

Using right hand rule, the direction of magnetic force is upwards.