Answer:
Specific heat capacity of iron (c) = -0.04 J/g°C
Step-by-step explanation:
Given:
Mass of sample of iron M = 716.4 gram
Change in temperature Δt = -33.47°C
Heat energy Q = 996.6 joules
Find:
Specific heat capacity of iron (c)
Computation:
We know that
Q = McΔt
So,
c = Q / M[Δt]
Specific heat capacity of iron (c) = 996.6 / (716.4)(-33.47)
Specific heat capacity of iron (c) = 996.6 / -23,977.908
Specific heat capacity of iron (c) = -0.0415
Specific heat capacity of iron (c) = -0.04 J/g°C