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What are the two roots of the quadratic equation? y=x squared-3x-4

1 Answer

2 votes

Answer:

x ∈ R, 4,-1

Explanation:


y=x^2-3x-4


y=x^2+x-4x-4


y=(x^2+x)+(-4x-4)


y=x(x+1)+(-4)(x+1) Distributive property


y=(x+(-4))(x+1) Distributive Property


y=(x-4)(x+1)

set y to 0


0=(x-4)(x+1)

set the factors to 0


0=x-4; 0=x+1


4=x; -1=x

User John Kuriakose
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