For
a
x
2
+
b
x
+
c
=
0
, the values of
x
which are the solutions to the equation are given by:
x
=
−
b
±
√
b
2
−
4
a
c
2
a
Substituting
9
for
a
;
6
for
b
and
1
for
c
gives:
x
=
−
6
±
√
6
2
−
(
4
⋅
9
⋅
1
)
2
⋅
9
x
=
−
6
±
√
36
−
36
2
⋅
9
x
=
−
6
±
√
0
2
⋅
9
x
=
−
6
±
0
2
⋅
9
x
=
−
6
18
x
=
−
1
3