Answer:
his acceleration rate is -0.00186 m/s²
Step-by-step explanation:
Given;
initial position of the car, x₀ = 100 miles = 160, 900 m ( 1 mile = 1609 m)
time of motion, t₀ = 60 minutes = 60 mins x 60 s = 3,600 s
final position of the car, x₁ = 150 miles = 241,350 m
time of motion, t₁ = 100 minutes = 100 mins x 60 s = 6,000 s
The initial velocity is calculated as;
u = 160, 900 m / 3,600 s
u = 44.694 m/s
The final velocity is calculated as;
v = 241,350 m / 6,000 s
v = 40.225 m/s
The acceleration is calculated as;
![a = (\Delta V)/(\Delta t) = (v- u)/(t_1 - t_ 0) = (40.225 - 44.694)/(6000-3600) = -0.00186 \ m/s^2\\\\](https://img.qammunity.org/2022/formulas/physics/high-school/jlh1jy724p8nyj1pn5r06hslpfa45rz6fb.png)
Therefore, his acceleration rate is -0.00186 m/s²