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Trapezoid DEFG is dilated by scale factor of 2\3 to form trapezoid D'E'FG. Side E'F' measures 32. What is the measure of side EF?

User Dagray
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1 Answer

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Answer: 48

Explanation:

Given

Trapezoid DEFG is dilated by a scale factor of
(2)/(3)


E'F'=32

Suppose the length of EF is
x

Multiply the side length of DEFG by
(2)/(3) to form E'F'


\Rightarrow E'F'=x* (2)/(3)\\\\\Rightarrow 32=x* (2)/(3)\\\\\Rightarrow x=16* 3\\\Rightarrow x=48


\therefore EF=48

User Esben Andersen
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