Question

Make up an equation of the form y = kx +b, the graph of which passes through the following points:

P (4, 1) and Q (3, –5)

Answer 1

Explanation:

m = (y2 - y1)/(x2-x1)

m = (-5 -1)/(3-4) = -6/-1 = 6

y = 6x + b

then

slope point form

y - y1 = m (x - x1)

y - 1 = 6 (x - 4)

y - 1 = 6x - 24

y = 6x - 23

Answer 2

y=6x-23

Explanation: