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Given the following system of equations, solve for 'X', 'y' and 'z. 2x - 32= -18 -4y + 2z = 4 3x + 10y= 1
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Given the following system of equations, solve for 'X', 'y' and 'z.

2x - 32= -18
-4y + 2z = 4
3x + 10y= 1

User Kendrea
by
5.4k points

2 Answers

3 votes
2x-32=-18 2x-=18+32 2x=14 x=7
-4y+2z=4 2z=4-4y z=2-2y
3x+10y=1 3x= 1-10y x= 1/3-10/3y
User Valodzka
by
5.0k points
4 votes

x=7, y=-2, and z=-2

just trust me on it

User Joe Volcano
by
5.3k points
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