Question

A certain volume of gas at 298kelvin is heated such that its Volume and pressure are now 4 times their original value. what is the new temperature​

Answer 1

Answer: The new temperature is 4768 K.

Step-by-step explanation:

Given:
`T_(1)` = 298 K,
`V_(1)` = V,
`P_(1)` = P

`T_(2)` = ?,
`V_(2)` = 4V,
`P_(2)` = 4P

Using the combined gas law formula as follows.

`(P_(1)V_(1))/(T_(1)) = (P_(2)V_(2))/(T_(2))`

Substitute the values into above formula as follows.

`(P_(1)V_(1))/(T_(1)) = (P_(2)V_(2))/(T_(2))\\(P * V)/(298 K) = (4P * 4V)/(T_(2))\\T_(2) = 4768 K`

Thus, we can conclude that the new temperature is 4768 K.