Question

The height of the apple trees in an orchard are normally distributed with a mean of 12.5 feet and a standard deviation of 1.2 feet what percentage of the apple trees are taller than 14.9 ft

Answer 1

2.275%

Explanation:

z = (x-μ)/σ, where

x is the raw score = 14.9 ft

μ is the population mean = 12.5 ft

σ is the population standard deviation = 1.2 ft

We are to find the percentage of the apple trees are taller than 14.9 ft,

This means x > 14.9, x greater than 14.9

Hence,

z = (14.9 - 12.5)/1.2

z = 2

Probability value from Z-Table:

P(x<14.9) = 0.97725

P(x>14.9) = 1 - P(x<14.9) = 0.02275

Converting to Percentage

= 0.02275 × 100

= 2.275%

Therefore, the percentage of the apple trees that are taller than 14.9 ft is 2.275%