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2 members of the 5-member math study group will present their project to the class. How many combinations of 2 members are possible from the 5-member study group?

User Akash Pal
by
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2 Answers

4 votes

Final answer:

To find the number of combinations of 2 members from a 5-member math study group, use the formula for combinations. In this case, there are 10 possible combinations of 2 members.

Step-by-step explanation:

To find the number of combinations of 2 members from a 5-member math study group, we can use the formula for combinations. The formula is given by nCr = n! / ((n-r)! * r!), where n is the total number of members and r is the number of members chosen. In this case, n = 5 and r = 2. Plugging these values into the formula, we get:

nCr = 5! / ((5-2)! * 2!) = 5! / (3! * 2!) = (5 * 4 * 3 * 2 * 1) / ((3 * 2 * 1) * (2 * 1)) = 10.

Therefore, there are 10 combinations of 2 members possible from the 5-member math study group.

User Conduit
by
8.8k points
4 votes

Answer:

2

Step-by-step explanation:

(,)=?

(,)=(5,2)

=5!(2!(5−2)!)

=5!2!×3!

= 10

User Hoakey
by
8.6k points

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