Question

You are given the balanced chemical equation below. If you start this chemical reaction with 0.53 moles of CH4 and 1.5 moles of O2, how many grams of CO2 is formed?CH4 + 2O2 => CO2.+ 2H2O32.9 g b 23.3 g c 19.5 g d 8.5 g e 39.3 g f none of these

Answer 1

b. 23.3g

Step-by-step explanation:

Based on the reaction:

CH₄ + 2O₂ → CO₂ + 2H₂O

To find the mass of CO2 produced we must find, as first, the limiting reactant. With limiting reactant we can find the moles and the mass of CO2 as follows:

Limiting reactant:

For a complete reaction of 0.53 moles of CH4 are necessaries:

0.53 moles CH4 * (2mol O2 / 1mol CH4) = 1.06 moles O2.

As there are 1.5 moles, CH4 is limiting reactant.

Moles CO2:

1 mole of CH4 produce 1 mole of CO2. That means the moles of CO2 formed are 0.53 moles.

Mass CO2 (Molar mass: 44.01g/mol)

0.53 moles CO2 * (44.01g / mol) =

b. 23.3g