Question

Factor: 0.25x^2 - 0.16y^4

Answer 1

0.25x^2 - 0.16y^4

Both terms are perfect squares so use the difference of squares formula

A^2 - b^2 = (a+b)(a-b) where a = 5x and b = 4y^2

Answer is 0.01(5x + 4y^2)(5x-4y^2)

Answer 2

Solution given:

0.25x^2 - 0.16y^4

[0.5x]²-[0.4y²]²

[Note: Using formula: x²-y²=(x+y)(x-y)]

(0.5x+0.4y²)(0.5x-0.4y²) is a required answer.