Question

An object decelerate uniformly from 60.0m/s to a stop in 10.0s what is it acceleration?

a. 6.0m/S2
b. -6.0/S2
c.600m/S2
d.-600m/S2
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Answer 1

Formula=(v-u)/t
(0-60)/10= -6.0m/s

Answer 2

I'm not 100% sure, but I think its a. 6.0m/s2