9514 1404 393
Answer:
see attached
Explanation:
The boundary lines of both inequalities are dashed lines, because neither includes the "or equal to" case. Shading is above the boundary line in both cases.
The boundary line of the first inequality has a y-intercept of +3 and a slope of 1, so goes up 1 unit for each 1 unit to the right of (0, 3).
The boundary line of the second inequality has a y-intercept of +1 and a slope of -2, so goes down 2 units for each 1 unit to the right of (0, 1).
The solution space is the top quadrant of the X where the boundary lines cross. That is where the two solution spaces overlap. It includes parts of quadrants I and II.