Question

Solve using the quadratic formula. Show all work. Write each solution in simplest form. No decimals.

Answer 1

Explanation:

`{x}^(2) + 3x - 5 = 0`

a =1. b = 3. c = -5

Quadratic equation

`x = \frac{ - b + \sqrt{ {b}^(2) - 4ac} }{2a} \\ = \frac{ - 3 \: + \sqrt{ {3}^(2) \: - 4(1)( - 5) } }{2} \\ = ( - 3 \: + \: √(29) )/(2)`

Note: the plus sign in the quadratic equation should read "+-"

Therefore, the roots of the quadratic equation are

`( - 3 \: + \: √(29) )/(2) \: \: and \: \: ( - 3 \: - \: √(29) )/(2)`