Question

Does anyone know this

Answer 1

Given:

The functions are:

`f(x)=x+7`

`g(x)=x^2-3`

To find:

The values f(g(4)), g(f(5)) and f(f(1)).

Solution:

We have,

`f(x)=x+7`

`g(x)=x^2-3`

(i) We need to find the value of f(g(4)).

`f(g(4))=f((4)^2-3)`

`f(g(4))=f(16-3)`

`f(g(4))=f(13)`

`f(g(4))=13+7`

`f(g(4))=20`

Therefore, the value of f(g(4)) is 20.

(ii) We need to find the value of g(f(5)).

`g(f(5))=g(5+7)`

`g(f(5))=g(12)`

`g(f(5))=(12)^2-3`

`g(f(5))=144-3`

`g(f(5))=141`

Therefore, the value of g(f(5)) is 141.

(iii) We need to find the value of f(f(1)).

`f(f(1))=f(1+7)`

`f(f(1))=f(8)`

`f(f(1))=8+7`

`f(f(1))=15`

Therefore, the value of f(f(1)) is 15.