Answer:
a. 5177 cm³
b. 3,451 cm³
c. 67%
Explanation:
Given:
Diameter of each ball (d) = 13 cm
Radius of the ball (r) = radius of the cylinder = ½(13) = 6.5 cm
Height of the cylinder (h) = the sum of the diameters of the 3 balls = 3(13) = 39 cm
a. Volume of cylinder = πr²h
Plug in the values
Volume of cylinder = π*6.5²*39 = 5176.56 ≈ 5177 cm³
b. Total volume of the three balls = 3(volume of 1 ball) = 3(volume of sphere) = 3(⁴/3πr³)
Plug in the value
Total volume of the 3 balls = 3(⁴/3*π*6.5³) = 3(1150.35) = 3,451.05 ≈ 3,451 cm³
c. % of volume of the container occupied by the 3 balls = total volume of the three balls / volume of cylinder × 100
Plug in the values
= 3,451/5177 × 100
= 66.6602279
≈ 67%