51.0k views
1 vote
Write the equation of a circle with a center at
(2, -9) and a radius of 7
Helpppp

User Joe Okatch
by
7.7k points

1 Answer

1 vote

Answer:


x^2+y^2+14y+36=0

Explanation:

Given that,

Center = (2,-9)

Radius of the circle, r = 7

We need to find the equation of a circle with a center at (2, -9) and a radius of 7. It can be given by :


(x-h)^2+(y-k)^2=r^2

Put h = 2, k = -9 and r = 7 So,


(x-2)^2+(y-(-9))^2=7^2\\\\x^2+4-4x+y^2+81+18y=49\\\\x^2+y^2+14y+85-49=0\\\\x^2+y^2+14y+36=0

Hence, this is the required solution.

User Monarch Wadia
by
7.7k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories