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Helpppppppppppppppppppp

Helpppppppppppppppppppp-example-1

1 Answer

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Given:

A rectangle with sides 40 and 25.

A circle with radius 8 inside the rectangle.

The area of circle is unshaded.

To find:

The probability that a point (randomly selected) will lie in the unshaded region.

Solution:

The area of the rectangle is:


A_1=Length* Width


A_1=40* 25


A_1=1000

The area of the circle is:


A_2=\pi r^2

Where, r is the radius.


A_2=\pi (8)^2


A_2=\pi (64)


A_2=64\pi


A_2\approx 201.06

The probability that a point (randomly selected) will lie in the unshaded region is:


\text{Probability}=\frac{\text{Unshaded region}}{\text{Total region}}


\text{Probability}=(A_2)/(A_1)


\text{Probability}=(201.06)/(1000)


\text{Probability}=0.20106

Therefore, the required probability is 0.20106.

User Vlr
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