Question

PLEASE HELP

How many moles of silane gas (SiH4) are present in 8.68 mL
measured at 18 0C and 1.50 atm?

Answer 1

Answer: There are 0.00054 moles of silane gas (SiH4) are present in 8.68 mL measured at 18 0C and 1.50 atm.

Step-by-step explanation:

Given: Volume = 8.68 mL (1 mL = 0.001 L) =
`8.68 * 10^(-3) L`,

Temperature =
`18^(o)C = (18 + 273) K = 291 K`,

Pressure = 1.50 atm

The ideal gas formula is as follows.

PV = nRT

where,

P = pressure

V = volume

n = no. of moles

R = gas constant = 0.0821 L atm/mol K

T = temperature

Substitute the values into above formula as follows.

`PV = nRT\\1.50 atm * 8.68 * 10^(-3) L = n * 0.0821 L atm/mol K * 291 K\\n = (1.50 atm * 8.68 * 10^(-3) L)/(0.0821 L atm/mol K * 291 K)\\= (0.01302)/(23.8911)\\= 0.00054 mol`

Thus, we can conclude that there are 0.00054 moles of silane gas (SiH4) are present in 8.68 mL measured at 18 0C and 1.50 atm.