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A block of metal has a mass of 18.361kg and the following dimensions: 22.35 cm x 7.34 cm x 22.05 mm. What is the density of the metal in g/cm^3

User Solenoid
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1 Answer

4 votes

Answer:

50.76 g/cm³

Step-by-step explanation:

We'll begin by converting 18.361 Kg to g. This can be obtained as follow:

1 Kg = 1000 g

Therefore,

18.361 Kg = 18.361 Kg × 1000 g / 1 Kg

18.361 Kg = 18361 g

Next, we shall express the dimension in the same unit of measurement.

Dimension = 22.35 cm x 7.34 cm x 22.05 mm

Thus, we shall convert 22.05 mm to cm. This can be obtained as follow:

10 mm = 1 cm

Therefore,

22.05 mm = 22.05 mm × 1 cm / 10 mm

22.05 mm = 2.205 cm

Thus, the dimension is 22.35 cm x 7.34 cm x 2.205 cm.

Next, we shall determine the volume of the metal. This can be obtained as follow:

Dimension = 22.35 cm x 7.34 cm x 2.205 cm.

Volume = 361.728045 cm³

Finally, we shall determine the density of the metal. This can be obtained as follow:

Mass of metal = 18361 g

Volume of metal = 361.728045 cm³

Density of metal =?

Density = mass / volume

Density of metal = 18361 / 361.728045

Density of metal = 50.76 g/cm³

User IronRoei
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