Question

What is the volume of 3.00 M sulfuric aid that contain 9.809 g of H2SO4 (98.09g/mol)

Answer 1

Given :

Molarity of sulfuric acid solution is 3.0 M.

Amount of sulfuric acid present in solution is 9.809 g.

To Find :

The volume of solution.

Solution :

We know, molarity is given by :

`Molarity = (number \ of \ moles * 1000)/(Volume\ ( ml ))\\\\M = (w * 1000)/(M.M * V)\\\\3 = (9.809* 1000)/(98.09 * V)\\\\V = (1000)/(10* 3)\ ml\\\\V = 33.33 \ ml`

Therefore, volume required is 33.33 ml .