Question

PLZZZZ HELP!!!!!!!!!!!!!!!!!

Answer 1

A=16.3 ft²

Explanation:

we are given a composite figure, composing of a triangle and a semicircle

first, let's find the area of the triangle

we are given the height (5 ft) and the base of the triangle (4 ft)

the formula for the area of the triangle is given as bh/2, where b is the base and h is the height

substitute the known values into the formula

`A_(triangle)`=bh/2

`A_(triangle)`=(5*4)/2

`A_(triangle)`=20/2=10 ft²

so the area of the triangle is 10 ft²

now to find the area of the semicircle:

the area of a semicircle is half the area of a circle; the area of a circle is given as πr², where r is the radius. Therefore, the area of a semicircle is (πr²)/2

4 ft isn't just the base of the triangle; it's also the diameter of the semicircle

however, we need the radius

the radius is half the diameter value

r=d/2

r=4/2

r=2 ft

so the radius is 4 feet

now find the area of the semicircle. Don't substitute for π just yet.

`A_(semicircle)`=(πr²)/2

`A_(semicircle)`=(π*2²)/2

`A_(semicircle)`=4π/2

`A_(semicircle)`=2π

π is often substituted as 3.14 or 22/7

so if we used 3.14 for instance:

`A_(semicircle)`=6.28; rounded to the nearest tenth, that's 6.3 ft²

now add the two areas together to get the area of the composite figure

`A_(compositefigure)`=
`A_(triangle)`+
`A_(semicircle)`

`A_(compositefigure)`=10+6.3=16.3 ft²

Hope this helps! Good luck on your assignment!!