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Compute the Limit
\lim_(x \to \infty) ((log(x))^(2) )/(x)

1 Answer

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By applying L'Hopital's rule twice,


\displaystyle \lim_(x\to\infty) (\log^2(x))/(x) = \lim_(x\to\infty) \frac{\frac{2\log(x)}x}1 \\\\ = \lim_(x\to\infty) \frac{2\log(x)}x \\\\ = \lim_(x\to\infty) \frac{\frac2x}1 \\\\ = \lim_(x\to\infty)\frac2x = \boxed{0}

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