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circle c shown below was dilated with the origin as the center of dilation to create circle C' which rule represents the transformation?

circle c shown below was dilated with the origin as the center of dilation to create-example-1

2 Answers

3 votes

Answer:

  • A. (x, y) → (2/7x, 2/7y)

Explanation:

Equation of the smaller circle:

  • x² + y² = 2²

Equation of the greater circle:

  • x² + y² = 7²

The scale factor is the ratio of radiuses:

  • k = r₁ / r₂ = 2/7

So the rule is:

  • (x, y) → (kx, ky) = (2/7x, 2/7y)

Correct choice is A

circle c shown below was dilated with the origin as the center of dilation to create-example-1
User Merott
by
5.1k points
5 votes

Answer:


\sf A. \quad (x, y) \rightarrow \left((7)/(2)x, (7)/(2)y \right)

Explanation:

The distance from the center of the circle to any point on the circumference is the radius.

From inspection of the given graph:

  • Radius of Circle C (before dilation) = 2 units
  • Radius of Circle C' (after dilation) = 7 units

To find the scale factor of the dilation from the small circle C to the large circle C', divide the radius of the large circle by the radius of the small circle.

Therefore, the dilation is an enlargement of scale factor ⁷/₂ about the origin.

So the rule that represents the transformation is:


\sf (x, y) \rightarrow \left((7)/(2)x, (7)/(2)y \right)

Check (see attached):

Point (0, 2) is on circle C.


\implies \sf (0, 2) \rightarrow \left((7)/(2)(0), (7)/(2)(2) \right)=(0,7)

Point (1, √3) is on Circle C:


\implies \sf (1, √(3)) \rightarrow \left((7)/(2)(1), (7)/(2)(√(3)) \right)=\left(3.5,6.06)

circle c shown below was dilated with the origin as the center of dilation to create-example-1
User Eedeep
by
4.4k points