Answer:
Part A
a. There is not sufficient sample evidence to conclude that the full-time placement rate is now less than 87% because the p-value is greater than 0.05
Part B
= 17.9·(x) + 1.6
Part C
The teen pregnancy rate in Florida is 6.54
Explanation:
The percentage of graduates that find full-time employment in their fields within the first year of graduation = 87%
The significant level of the hypothesis test = 5% = 0.05
The p-value = 0.07
Given that the testing conditions are met, we have;
The p-value is larger than the significant level of 0.05, therefore, it cannot be concluded that there is significant difference between the two rates
Therefore;
There is not enough statistical evidence available to come to a conclusion that the placement rate of full-time students has reduced below the given 87% because from the statistics, the p-value is larger than 0.05.
Part B
Number of Pages, x; 7, 12, 4, 14, 25, 30
Cost, y; 128, 213, 75, 250, 446, 540
The regression analysis formula is;
Y = a + b·X
We have;
![b = (N\sum XY - \left (\sum X \right )\left (\sum Y \right ))/(N\sum X^(2) - \left (\sum X \right )^(2))](https://img.qammunity.org/2022/formulas/mathematics/college/gad7yiuba70s8rrbe5psl7c0ptm2lr9tgr.png)
∴ b = (6×34602-92×1652)/(6×1930 - 92²) ≈ 17.852
![a = (\sum Y - b\sum X)/(N)](https://img.qammunity.org/2022/formulas/mathematics/college/36sf533yhqi7e6cj6dht833m95e7p8m3yj.png)
a = (1652 - 17.852 × 92)/6 ≈ 1.6
∴ Y ≈ 17.9·(x) + 1.6
Part C
The given regression model is y = 4.3 + 1.4(x)
Therefore, at x = 1.6, we get;
y = 4.3 + 1.4 × 1.6 = 6.54
The suggests that the teen pregnancy rate in Florida is 6.54.